Basic Calculation for Transformer Fuse Selection



The selection of an 11kV High Tension (HT) fuse is critical to ensure the protection of electrical equipment, such as transformers and cables, in high voltage distribution systems. The correct fuse selection minimizes the risk of damage due to overcurrent or short-circuit conditions. Here’s how the calculation is typically done:

1. Understanding the Parameters

  • System Voltage: The rated voltage of the system (in this case, 11kV).
  • Full Load Current (FLC): This is the current that the equipment will draw under full-load conditions. It is usually provided by the manufacturer or calculated based on power ratings.
  • Short-Circuit Current: The maximum current that can flow through the system in case of a fault.
  • Transformer Rating: If you are protecting a transformer, the rating in kVA will be important in calculating the primary current.

2. Full Load Current Calculation

If the fuse is protecting a transformer, the full load current on the 11kV side can be calculated using the formula:

IFLC=Transformer Rating (kVA)3×Line Voltage (kV)I_{\text{FLC}} = \frac{\text{Transformer Rating (kVA)}}{\sqrt{3} \times \text{Line Voltage (kV)}}

If the fault level of the 11kV system is 250 MVA:

Isc=2503×1113,123AI_{\text{sc}} = \frac{250}{\sqrt{3} \times 11} \approx 13,123 \, \text{A}
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